Flooring · Hard Flooring

Hardwood Floor Replacement Cost, Permits and Who Does the Work

Removing an existing hardwood floor and installing a new one, typically handled by a flooring contractor.

Model reviewed August 2026

Typical cost

$7,500

National, standard scope

Range

$3,500 – $16,000

Low to high scope

Trade

Flooring contractor

DIY difficulty 2/5

Permit

Rarely required

Normally treated as maintenance

Do I need a permit for hardwood floor replacement?

Usually no

Hardwood Floor work of this type is normally treated as maintenance or a direct swap and is not typically permitted. Always confirm with the building department that has jurisdiction over your address.

Cost breakdown

Modeled national figures for a standard single-family job.

Low endSimple scope, easy access, no surprises$3,500
TypicalWhat most homeowners pay$7,500
High endLarge scope, upgrades or difficult conditions$16,000
Job typeProject
Cost varies by locationHigh

Variants

Distinct options within this job that buyers compare before committing.

SolidEngineeredOakHickoryWide plank

Calculators for this job

Related jobs

Related projects homeowners often plan together.

Also searched as

You may also hear this called:

replace hardwood floor · new hardwood floor · hardwood floor replacement cost · hardwood floor swap

Frequently asked questions

How much does hardwood floor replacement cost?

Most homeowners pay between $3,500 and $16,000, with $7,500 typical for a standard single-family job. Figures are modeled national estimates, not quotes.

Do I need a permit for hardwood floor work?

Usually not. This work is normally treated as maintenance or a like-for-like swap, so no permit is typically pulled.

Who does hardwood floor replacement?

A flooring contractor handles this job. DIY difficulty is rated 2/5 (5 = very DIY friendly).

Does the price change much by location?

Yes. Across the states we price, the typical cost ranges from $6,750 to $9,825 — about a 46% spread — driven by labor rates, code requirements and permit fees.